A point in figure is selected at random find the probability that the point will be in shaded region
Accepted Solution
A:
a - side of a squarer - radius of a circle[tex] |\Omega|=a^2\\ |A|=4\pi r^2\\ r=\dfrac{a}{4}\\ |A|=4\pi \cdot\left(\dfrac{a}{4}\right)^2=4\pi \cdot\dfrac{a^2}{16}=\dfrac{a^2\pi}{4}\\\\ P(A)=\dfrac{\dfrac{a^2\pi}{4}}{a^2}=\dfrac{\pi}{4}\approx 79\% [/tex]Hm, looks like none of the asnwers is correct.