The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = 1/4 (x – 8). What is the slope-intercept form of the equation for this line?y = y = 1/4x - 12.x – 12y = y = 1/4x - 4.x – 4y = y = 1/4x + 2.x + 2y = y = 1/4x + 6.x + 6

Answer:[tex]\large\boxed{y=\dfrac{1}{4}x+2}[/tex]Step-by-step explanation:The slope-intercept form of an equation of a line:[tex]y=mx+b[/tex]m - slopeb - y-interceptWe have the equation in the point-slope form.[tex]y-4=\dfrac{1}{4}(x-8)[/tex]Convert to the slope-intercept form:[tex]y-4=\dfrac{1}{4}(x-8)[/tex]    multiply both sides by 4[tex]4y-16=x-8[/tex]           add 16 to both sides[tex]4y=x+8[/tex]             divide both sides by 4[tex]y=\dfrac{1}{4}x+2[/tex]